Albert has 3 more 20-cent coins than 10-cent coins. After he used 16 of his 20-cent coins, the total value of 20-cent coins is $3.40 more than the total value of 10-cent coins. How many coins did he have at first?
|
20¢ |
10¢ |
Before |
1 u + 3 |
1 u |
Change |
- 16 |
|
After |
1 u - 13 |
1 u |
|
20¢ |
10¢ |
Number |
1 u - 13 |
1 u |
Value |
20 |
10 |
Total value |
20 u - 260 |
10 u |
$1 = 100¢
$3.40 = 340¢
Number of 20¢ coins in the end
= 1 u + 3 - 16
= 1 u - 13
Total value of 20¢ coins in the end
= 20 x (1 u - 13)
= 20 u - 260
Total value of 10¢ coins in the end
= 10 x 1 u
= 10 u
After using 16 20-cent coins, the value of 20-cent coins is 340¢ more than the value of 10-cent coins. If another 340¢ is added to the 10-cent coins, the total value of 20-cent coins and 10-cent coins will be the same.
20 u - 260 = 10 u + 340
20 u - 10 u = 340 + 260
10 u = 600
1 u = 600 ÷ 10 = 60
Number of coins that Albert had at first
= 1 u + 1 u + 3
= 2 u + 3
= (2 x 60) + 3
= 120 + 3
= 123
Answer(s): 123