Andy has 9 more 20-cent coins than 10-cent coins. After he used 15 of his 20-cent coins, the total value of 20-cent coins is $3.70 more than the total value of 10-cent coins. How many coins did he have at first?
|
20¢ |
10¢ |
Before |
1 u + 9 |
1 u |
Change |
- 15 |
|
After |
1 u - 6 |
1 u |
|
20¢ |
10¢ |
Number |
1 u - 6 |
1 u |
Value |
20 |
10 |
Total value |
20 u - 120 |
10 u |
$1 = 100¢
$3.70 = 370¢
Number of 20¢ coins in the end
= 1 u + 9 - 15
= 1 u - 6
Total value of 20¢ coins in the end
= 20 x (1 u - 6)
= 20 u - 120
Total value of 10¢ coins in the end
= 10 x 1 u
= 10 u
After using 15 20-cent coins, the value of 20-cent coins is 370¢ more than the value of 10-cent coins. If another 370¢ is added to the 10-cent coins, the total value of 20-cent coins and 10-cent coins will be the same.
20 u - 120 = 10 u + 370
20 u - 10 u = 370 + 120
10 u = 490
1 u = 490 ÷ 10 = 49
Number of coins that Andy had at first
= 1 u + 1 u + 9
= 2 u + 9
= (2 x 49) + 9
= 98 + 9
= 107
Answer(s): 107