Gabriel has 4 more 20-cent coins than 10-cent coins. After he used 7 of his 20-cent coins, the total value of 20-cent coins is $1.80 more than the total value of 10-cent coins. How many coins did he have at first?
|
20¢ |
10¢ |
Before |
1 u + 4 |
1 u |
Change |
- 7 |
|
After |
1 u - 3 |
1 u |
|
20¢ |
10¢ |
Number |
1 u - 3 |
1 u |
Value |
20 |
10 |
Total value |
20 u - 60 |
10 u |
$1 = 100¢
$1.80 = 180¢
Number of 20¢ coins in the end
= 1 u + 4 - 7
= 1 u - 3
Total value of 20¢ coins in the end
= 20 x (1 u - 3)
= 20 u - 60
Total value of 10¢ coins in the end
= 10 x 1 u
= 10 u
After using 7 20-cent coins, the value of 20-cent coins is 180¢ more than the value of 10-cent coins. If another 180¢ is added to the 10-cent coins, the total value of 20-cent coins and 10-cent coins will be the same.
20 u - 60 = 10 u + 180
20 u - 10 u = 180 + 60
10 u = 240
1 u = 240 ÷ 10 = 24
Number of coins that Gabriel had at first
= 1 u + 1 u + 4
= 2 u + 4
= (2 x 24) + 4
= 48 + 4
= 52
Answer(s): 52