Dylan has 3 more 10-cent coins than 5-cent coins. After he used 10 of his 10-cent coins, the total value of 10-cent coins is $4.60 more than the total value of 5-cent coins. How many coins did he have at first?
|
10¢ |
5¢ |
Before |
1 u + 3 |
1 u |
Change |
- 10 |
|
After |
1 u - 7 |
1 u |
|
10¢ |
5¢ |
Number |
1 u - 7 |
1 u |
Value |
10 |
5 |
Total value |
10 u - 70 |
5 u |
$1 = 100¢
$4.60 = 460¢
Number of 10¢ coins in the end
= 1 u + 3 - 10
= 1 u - 7
Total value of 10¢ coins in the end
= 10 x (1 u - 7)
= 10 u - 70
Total value of 5¢ coins in the end
= 5 x 1 u
= 5 u
After using 10 10-cent coins, the value of 10-cent coins is 460¢ more than the value of 5-cent coins. If another 460¢ is added to the 5-cent coins, the total value of 10-cent coins and 5-cent coins will be the same.
10 u - 70 = 5 u + 460
10 u - 5 u = 460 + 70
5 u = 530
1 u = 530 ÷ 5 = 106
Number of coins that Dylan had at first
= 1 u + 1 u + 3
= 2 u + 3
= (2 x 106) + 3
= 212 + 3
= 215
Answer(s): 215