Some identical novels can be arranged in exactly 14 per row. If the same number of novels is arranged in rows of 10 novels each, there will be 3 more rows but short of 2 novels. How many novels are there altogether?
| |
14 per row |
10 per row |
| Number |
1 u |
1 u + 3 |
| Value |
14 u |
10 |
| Total value |
14 u |
10 u + 30 - 2 |
Number of rows if the novels are arranged in rows of 14 = 1 u
Number of rows if the novels are arranged in rows of 10 = 1 u + 3
Total number of novels if they are arranged in rows of 14
= 14 x 1 u
= 14 u
Total number of novels if they are arranged in rows of 10
= 10 x (1 u + 3) - 2
= 10 u + 30 - 2
= 10 u + 28
The total number of novels remains the same for both cases.
14 u = 10 u + 28
14 u - 10 u = 28
4 u = 28
1 u = 28 ÷ 4 = 7
Total number of novels
= 14 u
= 14 x 7
= 98
Answer(s): 98
