Some identical novels can be arranged in exactly 14 per row. If the same number of novels is arranged in rows of 8 novels each, there will be 6 more rows but short of 6 novels. How many novels are there altogether?
| |
14 per row |
8 per row |
| Number |
1 u |
1 u + 6 |
| Value |
14 u |
8 |
| Total value |
14 u |
8 u + 48 - 6 |
Number of rows if the novels are arranged in rows of 14 = 1 u
Number of rows if the novels are arranged in rows of 8 = 1 u + 6
Total number of novels if they are arranged in rows of 14
= 14 x 1 u
= 14 u
Total number of novels if they are arranged in rows of 8
= 8 x (1 u + 6) - 6
= 8 u + 48 - 6
= 8 u + 42
The total number of novels remains the same for both cases.
14 u = 8 u + 42
14 u - 8 u = 42
6 u = 42
1 u = 42 ÷ 6 = 7
Total number of novels
= 14 u
= 14 x 7
= 98
Answer(s): 98
