Some identical novels can be arranged in exactly 12 per row. If the same number of novels is arranged in rows of 7 novels each, there will be 5 more rows but short of 5 novels. How many novels are there altogether?
|
12 per row |
7 per row |
Number |
1 u |
1 u + 5 |
Value |
12 u |
7 |
Total value |
12 u |
7 u + 35 - 5 |
Number of rows if the novels are arranged in rows of 12 = 1 u
Number of rows if the novels are arranged in rows of 7 = 1 u + 5
Total number of novels if they are arranged in rows of 12
= 12 x 1 u
= 12 u
Total number of novels if they are arranged in rows of 7
= 7 x (1 u + 5) - 5
= 7 u + 35 - 5
= 7 u + 30
The total number of novels remains the same for both cases.
12 u = 7 u + 30
12 u - 7 u = 30
5 u = 30
1 u = 30 ÷ 5 = 6
Total number of novels
= 12 u
= 12 x 6
= 72
Answer(s): 72