Jane and Marion shared some stamps. Jane had 75% of what Marion had at first. Jane then gave Marion
58 of what she had. How many more percent did Marion have than Jane in the end? Correct the answer to 1 decimal place.
|
Jane |
Marion |
Comparing Jane and Marion at first |
4x2 = 8 u |
3x2 = 6 u |
Before |
8x1 = 8 u |
|
Change |
- 5x1 = - 5 u |
+ 5x1 = + 5 u |
After |
3x1 = 3 u |
11 u |
75% =
75100 =
34The number of stamps that Jane had at first is repeated. Make the number of stamps that Jane had at first the same. LCM of 4 and 8 is 8.
Number of stamps that Marion had in the end
= 6 u + 5 u
= 11 u
Number of more stamps that Marion had than Jane in the end
= 11 u - 3 u
= 8 u
Number of more stamps that Marion had than Jane in the end in percent
=
83 x 100%
≈ 266.7%
Answer(s): 266.7%