Sarah and Irene shared some coins. Sarah had 60% of what Irene had at first. Sarah then gave Irene
47 of what she had. How many more percent did Irene have than Sarah in the end? Correct the answer to 1 decimal place.
|
Sarah |
Irene |
Comparing Sarah and Irene at first |
5x7 = 35 u |
3x7 = 21 u |
Before |
7x5 = 35 u |
|
Change |
- 4x5 = - 20 u |
+ 4x5 = + 20 u |
After |
3x5 = 15 u |
41 u |
60% =
60100 =
35The number of coins that Sarah had at first is repeated. Make the number of coins that Sarah had at first the same. LCM of 5 and 7 is 35.
Number of coins that Irene had in the end
= 21 u + 20 u
= 41 u
Number of more coins that Irene had than Sarah in the end
= 41 u - 15 u
= 26 u
Number of more coins that Irene had than Sarah in the end in percent
=
2615 x 100%
≈ 173.3%
Answer(s): 173.3%