Min and Opal shared some cards. Min had 70% of what Opal had at first. Min then gave Opal
57 of what she had. How many less percent did Min have than Opal in the end? Correct the answer to 1 decimal place.
| |
Min |
Opal |
Comparing Min
and Opal at first |
10x7 =
70 u |
7x7 =
49 u |
| Before |
7x10 =
70 u |
|
| Change |
- 5x10 =
- 50 u |
+ 5x10 =
+ 50 u |
| After |
2x10 =
20 u |
99 u |
70% =
70100 =
710The number of cards that Min had at first is repeated. Make the number of cards that Min had at first the same. LCM of 10 and 7 is 70.
Number of cards that Opal had in the end
= 49 u + 50 u
= 99 u
Number of less cards that Min had than Opal in the end
= 99 u - 20 u
= 79 u
Number of less cards that Min had than Opal in the end in percent
=
7999 x 100%
≈ 79.8%
Answer(s): 79.8%
