Kimberly and Diana shared some cards. Kimberly had 60% of what Diana had at first. Kimberly then gave Diana
38 of what she had. How many less percent did Kimberly have than Diana in the end? Correct the answer to 1 decimal place.
| |
Kimberly |
Diana |
Comparing Kimberly
and Diana at first |
5x8 =
40 u |
3x8 =
24 u |
| Before |
8x5 =
40 u |
|
| Change |
- 3x5 =
- 15 u |
+ 3x5 =
+ 15 u |
| After |
5x5 =
25 u |
39 u |
60% =
60100 =
35The number of cards that Kimberly had at first is repeated. Make the number of cards that Kimberly had at first the same. LCM of 5 and 8 is 40.
Number of cards that Diana had in the end
= 24 u + 15 u
= 39 u
Number of less cards that Kimberly had than Diana in the end
= 39 u - 25 u
= 14 u
Number of less cards that Kimberly had than Diana in the end in percent
=
1439 x 100%
≈ 35.9%
Answer(s): 35.9%
