Kimberly and Abi shared some pens. Kimberly had 75% of what Abi had at first. Kimberly then gave Abi
47 of what she had. How many more percent did Abi have than Kimberly in the end? Correct the answer to 1 decimal place.
|
Kimberly |
Abi |
Comparing Kimberly and Abi at first |
4x7 = 28 u |
3x7 = 21 u |
Before |
7x4 = 28 u |
|
Change |
- 4x4 = - 16 u |
+ 4x4 = + 16 u |
After |
3x4 = 12 u |
37 u |
75% =
75100 =
34The number of pens that Kimberly had at first is repeated. Make the number of pens that Kimberly had at first the same. LCM of 4 and 7 is 28.
Number of pens that Abi had in the end
= 21 u + 16 u
= 37 u
Number of more pens that Abi had than Kimberly in the end
= 37 u - 12 u
= 25 u
Number of more pens that Abi had than Kimberly in the end in percent
=
2512 x 100%
≈ 208.3%
Answer(s): 208.3%