Kimberly and Jean shared some marbles. Kimberly had 40% of what Jean had at first. Kimberly then gave Jean
58 of what she had. How many more percent did Jean have than Kimberly in the end? Correct the answer to 1 decimal place.
| |
Kimberly |
Jean |
Comparing Kimberly
and Jean at first |
5x8 =
40 u |
2x8 =
16 u |
| Before |
8x5 =
40 u |
|
| Change |
- 5x5 =
- 25 u |
+ 5x5 =
+ 25 u |
| After |
3x5 =
15 u |
41 u |
40% =
40100 =
25The number of marbles that Kimberly had at first is repeated. Make the number of marbles that Kimberly had at first the same. LCM of 5 and 8 is 40.
Number of marbles that Jean had in the end
= 16 u + 25 u
= 41 u
Number of more marbles that Jean had than Kimberly in the end
= 41 u - 15 u
= 26 u
Number of more marbles that Jean had than Kimberly in the end in percent
=
2615 x 100%
≈ 173.3%
Answer(s): 173.3%
