Gem and Sabrina shared some coins. Gem had 50% of what Sabrina had at first. Gem then gave Sabrina
38 of what she had. How many less percent did Gem have than Sabrina in the end? Correct the answer to 1 decimal place.
|
Gem |
Sabrina |
Comparing Gem and Sabrina at first |
2x4 = 8 u |
1x4 = 4 u |
Before |
8x1 = 8 u |
|
Change |
- 3x1 = - 3 u |
+ 3x1 = + 3 u |
After |
5x1 = 5 u |
7 u |
50% =
50100 =
12The number of coins that Gem had at first is repeated. Make the number of coins that Gem had at first the same. LCM of 2 and 8 is 8.
Number of coins that Sabrina had in the end
= 4 u + 3 u
= 7 u
Number of less coins that Gem had than Sabrina in the end
= 7 u - 5 u
= 2 u
Number of less coins that Gem had than Sabrina in the end in percent
=
27 x 100%
≈ 28.6%
Answer(s): 28.6%