Jen and Penelope shared some cards. Jen had 70% of what Penelope had at first. Jen then gave Penelope
25 of what she had. How many more percent did Penelope have than Jen in the end? Correct the answer to 1 decimal place.
|
Jen |
Penelope |
Comparing Jen and Penelope at first |
10x1 = 10 u |
7x1 = 7 u |
Before |
5x2 = 10 u |
|
Change |
- 2x2 = - 4 u |
+ 2x2 = + 4 u |
After |
3x2 = 6 u |
11 u |
70% =
70100 =
710The number of cards that Jen had at first is repeated. Make the number of cards that Jen had at first the same. LCM of 10 and 5 is 10.
Number of cards that Penelope had in the end
= 7 u + 4 u
= 11 u
Number of more cards that Penelope had than Jen in the end
= 11 u - 6 u
= 5 u
Number of more cards that Penelope had than Jen in the end in percent
=
56 x 100%
≈ 83.3%
Answer(s): 83.3%