Julie and Esther shared some coins. Julie had 70% of what Esther had at first. Julie then gave Esther
25 of what she had. How many less percent did Julie have than Esther in the end? Correct the answer to 1 decimal place.
| |
Julie |
Esther |
Comparing Julie
and Esther at first |
10x1 =
10 u |
7x1 =
7 u |
| Before |
5x2 =
10 u |
|
| Change |
- 2x2 =
- 4 u |
+ 2x2 =
+ 4 u |
| After |
3x2 =
6 u |
11 u |
70% =
70100 =
710The number of coins that Julie had at first is repeated. Make the number of coins that Julie had at first the same. LCM of 10 and 5 is 10.
Number of coins that Esther had in the end
= 7 u + 4 u
= 11 u
Number of less coins that Julie had than Esther in the end
= 11 u - 6 u
= 5 u
Number of less coins that Julie had than Esther in the end in percent
=
511 x 100%
≈ 45.5%
Answer(s): 45.5%
