Jen and Tina shared some stamps. Jen had 60% of what Tina had at first. Jen then gave Tina
58 of what she had. How many more percent did Tina have than Jen in the end? Correct the answer to 1 decimal place.
| |
Jen |
Tina |
Comparing Jen
and Tina at first |
5x8 =
40 u |
3x8 =
24 u |
| Before |
8x5 =
40 u |
|
| Change |
- 5x5 =
- 25 u |
+ 5x5 =
+ 25 u |
| After |
3x5 =
15 u |
49 u |
60% =
60100 =
35The number of stamps that Jen had at first is repeated. Make the number of stamps that Jen had at first the same. LCM of 5 and 8 is 40.
Number of stamps that Tina had in the end
= 24 u + 25 u
= 49 u
Number of more stamps that Tina had than Jen in the end
= 49 u - 15 u
= 34 u
Number of more stamps that Tina had than Jen in the end in percent
=
3415 x 100%
≈ 226.7%
Answer(s): 226.7%
