Jaslyn and Nicole shared some coins. Jaslyn had 70% of what Nicole had at first. Jaslyn then gave Nicole
35 of what she had. How many less percent did Jaslyn have than Nicole in the end? Correct the answer to 1 decimal place.
| |
Jaslyn |
Nicole |
Comparing Jaslyn
and Nicole at first |
10x1 =
10 u |
7x1 =
7 u |
| Before |
5x2 =
10 u |
|
| Change |
- 3x2 =
- 6 u |
+ 3x2 =
+ 6 u |
| After |
2x2 =
4 u |
13 u |
70% =
70100 =
710The number of coins that Jaslyn had at first is repeated. Make the number of coins that Jaslyn had at first the same. LCM of 10 and 5 is 10.
Number of coins that Nicole had in the end
= 7 u + 6 u
= 13 u
Number of less coins that Jaslyn had than Nicole in the end
= 13 u - 4 u
= 9 u
Number of less coins that Jaslyn had than Nicole in the end in percent
=
913 x 100%
≈ 69.2%
Answer(s): 69.2%
