Dana and Abi shared some marbles. Dana had 70% of what Abi had at first. Dana then gave Abi
58 of what she had. How many more percent did Abi have than Dana in the end? Correct the answer to 1 decimal place.
| |
Dana |
Abi |
Comparing Dana
and Abi at first |
10x4 =
40 u |
7x4 =
28 u |
| Before |
8x5 =
40 u |
|
| Change |
- 5x5 =
- 25 u |
+ 5x5 =
+ 25 u |
| After |
3x5 =
15 u |
53 u |
70% =
70100 =
710The number of marbles that Dana had at first is repeated. Make the number of marbles that Dana had at first the same. LCM of 10 and 8 is 40.
Number of marbles that Abi had in the end
= 28 u + 25 u
= 53 u
Number of more marbles that Abi had than Dana in the end
= 53 u - 15 u
= 38 u
Number of more marbles that Abi had than Dana in the end in percent
=
3815 x 100%
≈ 253.3%
Answer(s): 253.3%
