Min and Yoko shared some pens. Min had 50% of what Yoko had at first. Min then gave Yoko
58 of what she had. How many less percent did Min have than Yoko in the end? Correct the answer to 1 decimal place.
| |
Min |
Yoko |
Comparing Min
and Yoko at first |
2x4 =
8 u |
1x4 =
4 u |
| Before |
8x1 =
8 u |
|
| Change |
- 5x1 =
- 5 u |
+ 5x1 =
+ 5 u |
| After |
3x1 =
3 u |
9 u |
50% =
50100 =
12The number of pens that Min had at first is repeated. Make the number of pens that Min had at first the same. LCM of 2 and 8 is 8.
Number of pens that Yoko had in the end
= 4 u + 5 u
= 9 u
Number of less pens that Min had than Yoko in the end
= 9 u - 3 u
= 6 u
Number of less pens that Min had than Yoko in the end in percent
=
69 x 100%
≈ 66.7%
Answer(s): 66.7%
