Tina and Roshel shared some stamps. Tina had 80% of what Roshel had at first. Tina then gave Roshel
58 of what she had. How many less percent did Tina have than Roshel in the end? Correct the answer to 1 decimal place.
| |
Tina |
Roshel |
Comparing Tina
and Roshel at first |
5x8 =
40 u |
4x8 =
32 u |
| Before |
8x5 =
40 u |
|
| Change |
- 5x5 =
- 25 u |
+ 5x5 =
+ 25 u |
| After |
3x5 =
15 u |
57 u |
80% =
80100 =
45The number of stamps that Tina had at first is repeated. Make the number of stamps that Tina had at first the same. LCM of 5 and 8 is 40.
Number of stamps that Roshel had in the end
= 32 u + 25 u
= 57 u
Number of less stamps that Tina had than Roshel in the end
= 57 u - 15 u
= 42 u
Number of less stamps that Tina had than Roshel in the end in percent
=
4257 x 100%
≈ 73.7%
Answer(s): 73.7%
