Gem and Jade shared some beads. Gem had 70% of what Jade had at first. Gem then gave Jade
58 of what she had. How many more percent did Jade have than Gem in the end? Correct the answer to 1 decimal place.
| |
Gem |
Jade |
Comparing Gem
and Jade at first |
10x4 =
40 u |
7x4 =
28 u |
| Before |
8x5 =
40 u |
|
| Change |
- 5x5 =
- 25 u |
+ 5x5 =
+ 25 u |
| After |
3x5 =
15 u |
53 u |
70% =
70100 =
710The number of beads that Gem had at first is repeated. Make the number of beads that Gem had at first the same. LCM of 10 and 8 is 40.
Number of beads that Jade had in the end
= 28 u + 25 u
= 53 u
Number of more beads that Jade had than Gem in the end
= 53 u - 15 u
= 38 u
Number of more beads that Jade had than Gem in the end in percent
=
3815 x 100%
≈ 253.3%
Answer(s): 253.3%
