Betty and Penelope shared some erasers. Betty had 60% of what Penelope had at first. Betty then gave Penelope
78 of what she had. How many less percent did Betty have than Penelope in the end? Correct the answer to 1 decimal place.
| |
Betty |
Penelope |
Comparing Betty
and Penelope at first |
5x8 =
40 u |
3x8 =
24 u |
| Before |
8x5 =
40 u |
|
| Change |
- 7x5 =
- 35 u |
+ 7x5 =
+ 35 u |
| After |
1x5 =
5 u |
59 u |
60% =
60100 =
35The number of erasers that Betty had at first is repeated. Make the number of erasers that Betty had at first the same. LCM of 5 and 8 is 40.
Number of erasers that Penelope had in the end
= 24 u + 35 u
= 59 u
Number of less erasers that Betty had than Penelope in the end
= 59 u - 5 u
= 54 u
Number of less erasers that Betty had than Penelope in the end in percent
=
5459 x 100%
≈ 91.5%
Answer(s): 91.5%
