Gem and Jean shared some coins. Gem had 70% of what Jean had at first. Gem then gave Jean
37 of what she had. How many less percent did Gem have than Jean in the end? Correct the answer to 1 decimal place.
|
Gem |
Jean |
Comparing Gem and Jean at first |
10x7 = 70 u |
7x7 = 49 u |
Before |
7x10 = 70 u |
|
Change |
- 3x10 = - 30 u |
+ 3x10 = + 30 u |
After |
4x10 = 40 u |
79 u |
70% =
70100 =
710The number of coins that Gem had at first is repeated. Make the number of coins that Gem had at first the same. LCM of 10 and 7 is 70.
Number of coins that Jean had in the end
= 49 u + 30 u
= 79 u
Number of less coins that Gem had than Jean in the end
= 79 u - 40 u
= 39 u
Number of less coins that Gem had than Jean in the end in percent
=
3979 x 100%
≈ 49.4%
Answer(s): 49.4%