Joelle and Julie shared some coins. Joelle had 70% of what Julie had at first. Joelle then gave Julie
45 of what she had. How many less percent did Joelle have than Julie in the end? Correct the answer to 1 decimal place.
| |
Joelle |
Julie |
Comparing Joelle
and Julie at first |
10x1 =
10 u |
7x1 =
7 u |
| Before |
5x2 =
10 u |
|
| Change |
- 4x2 =
- 8 u |
+ 4x2 =
+ 8 u |
| After |
1x2 =
2 u |
15 u |
70% =
70100 =
710The number of coins that Joelle had at first is repeated. Make the number of coins that Joelle had at first the same. LCM of 10 and 5 is 10.
Number of coins that Julie had in the end
= 7 u + 8 u
= 15 u
Number of less coins that Joelle had than Julie in the end
= 15 u - 2 u
= 13 u
Number of less coins that Joelle had than Julie in the end in percent
=
1315 x 100%
≈ 86.7%
Answer(s): 86.7%
