Marion and Linda shared some stamps. Marion had 75% of what Linda had at first. Marion then gave Linda
37 of what she had. How many more percent did Linda have than Marion in the end? Correct the answer to 1 decimal place.
| |
Marion |
Linda |
Comparing Marion
and Linda at first |
4x7 =
28 u |
3x7 =
21 u |
| Before |
7x4 =
28 u |
|
| Change |
- 3x4 =
- 12 u |
+ 3x4 =
+ 12 u |
| After |
4x4 =
16 u |
33 u |
75% =
75100 =
34The number of stamps that Marion had at first is repeated. Make the number of stamps that Marion had at first the same. LCM of 4 and 7 is 28.
Number of stamps that Linda had in the end
= 21 u + 12 u
= 33 u
Number of more stamps that Linda had than Marion in the end
= 33 u - 16 u
= 17 u
Number of more stamps that Linda had than Marion in the end in percent
=
1716 x 100%
≈ 106.3%
Answer(s): 106.3%
