Cathy and Abi shared some stickers. Cathy had 30% of what Abi had at first. Cathy then gave Abi
47 of what she had. How many more percent did Abi have than Cathy in the end? Correct the answer to 1 decimal place.
|
Cathy |
Abi |
Comparing Cathy and Abi at first |
10x7 = 70 u |
3x7 = 21 u |
Before |
7x10 = 70 u |
|
Change |
- 4x10 = - 40 u |
+ 4x10 = + 40 u |
After |
3x10 = 30 u |
61 u |
30% =
30100 =
310The number of stickers that Cathy had at first is repeated. Make the number of stickers that Cathy had at first the same. LCM of 10 and 7 is 70.
Number of stickers that Abi had in the end
= 21 u + 40 u
= 61 u
Number of more stickers that Abi had than Cathy in the end
= 61 u - 30 u
= 31 u
Number of more stickers that Abi had than Cathy in the end in percent
=
3130 x 100%
≈ 103.3%
Answer(s): 103.3%