Yoko and Marion shared some coins. Yoko had 30% of what Marion had at first. Yoko then gave Marion
58 of what she had. How many more percent did Marion have than Yoko in the end? Correct the answer to 1 decimal place.
| |
Yoko |
Marion |
Comparing Yoko
and Marion at first |
10x4 =
40 u |
3x4 =
12 u |
| Before |
8x5 =
40 u |
|
| Change |
- 5x5 =
- 25 u |
+ 5x5 =
+ 25 u |
| After |
3x5 =
15 u |
37 u |
30% =
30100 =
310The number of coins that Yoko had at first is repeated. Make the number of coins that Yoko had at first the same. LCM of 10 and 8 is 40.
Number of coins that Marion had in the end
= 12 u + 25 u
= 37 u
Number of more coins that Marion had than Yoko in the end
= 37 u - 15 u
= 22 u
Number of more coins that Marion had than Yoko in the end in percent
=
2215 x 100%
≈ 146.7%
Answer(s): 146.7%
