Sabrina and Irene shared some marbles. Sabrina had 60% of what Irene had at first. Sabrina then gave Irene
57 of what she had. How many less percent did Sabrina have than Irene in the end? Correct the answer to 1 decimal place.
| |
Sabrina |
Irene |
Comparing Sabrina
and Irene at first |
5x7 =
35 u |
3x7 =
21 u |
| Before |
7x5 =
35 u |
|
| Change |
- 5x5 =
- 25 u |
+ 5x5 =
+ 25 u |
| After |
2x5 =
10 u |
46 u |
60% =
60100 =
35The number of marbles that Sabrina had at first is repeated. Make the number of marbles that Sabrina had at first the same. LCM of 5 and 7 is 35.
Number of marbles that Irene had in the end
= 21 u + 25 u
= 46 u
Number of less marbles that Sabrina had than Irene in the end
= 46 u - 10 u
= 36 u
Number of less marbles that Sabrina had than Irene in the end in percent
=
3646 x 100%
≈ 78.3%
Answer(s): 78.3%
