Min and Dana shared some buttons. Min had 40% of what Dana had at first. Min then gave Dana
47 of what she had. How many more percent did Dana have than Min in the end? Correct the answer to 1 decimal place.
|
Min |
Dana |
Comparing Min and Dana at first |
5x7 = 35 u |
2x7 = 14 u |
Before |
7x5 = 35 u |
|
Change |
- 4x5 = - 20 u |
+ 4x5 = + 20 u |
After |
3x5 = 15 u |
34 u |
40% =
40100 =
25The number of buttons that Min had at first is repeated. Make the number of buttons that Min had at first the same. LCM of 5 and 7 is 35.
Number of buttons that Dana had in the end
= 14 u + 20 u
= 34 u
Number of more buttons that Dana had than Min in the end
= 34 u - 15 u
= 19 u
Number of more buttons that Dana had than Min in the end in percent
=
1915 x 100%
≈ 126.7%
Answer(s): 126.7%