Kimberly and Sabrina shared some beads. Kimberly had 25% of what Sabrina had at first. Kimberly then gave Sabrina
47 of what she had. How many more percent did Sabrina have than Kimberly in the end? Correct the answer to 1 decimal place.
| |
Kimberly |
Sabrina |
Comparing Kimberly
and Sabrina at first |
4x7 =
28 u |
1x7 =
7 u |
| Before |
7x4 =
28 u |
|
| Change |
- 4x4 =
- 16 u |
+ 4x4 =
+ 16 u |
| After |
3x4 =
12 u |
23 u |
25% =
25100 =
14The number of beads that Kimberly had at first is repeated. Make the number of beads that Kimberly had at first the same. LCM of 4 and 7 is 28.
Number of beads that Sabrina had in the end
= 7 u + 16 u
= 23 u
Number of more beads that Sabrina had than Kimberly in the end
= 23 u - 12 u
= 11 u
Number of more beads that Sabrina had than Kimberly in the end in percent
=
1112 x 100%
≈ 91.7%
Answer(s): 91.7%
