Nora and Betty shared some erasers. Nora had 75% of what Betty had at first. Nora then gave Betty
57 of what she had. How many less percent did Nora have than Betty in the end? Correct the answer to 1 decimal place.
| |
Nora |
Betty |
Comparing Nora
and Betty at first |
4x7 =
28 u |
3x7 =
21 u |
| Before |
7x4 =
28 u |
|
| Change |
- 5x4 =
- 20 u |
+ 5x4 =
+ 20 u |
| After |
2x4 =
8 u |
41 u |
75% =
75100 =
34The number of erasers that Nora had at first is repeated. Make the number of erasers that Nora had at first the same. LCM of 4 and 7 is 28.
Number of erasers that Betty had in the end
= 21 u + 20 u
= 41 u
Number of less erasers that Nora had than Betty in the end
= 41 u - 8 u
= 33 u
Number of less erasers that Nora had than Betty in the end in percent
=
3341 x 100%
≈ 80.5%
Answer(s): 80.5%
