Tammy and Abi shared some coins. Tammy had 40% of what Abi had at first. Tammy then gave Abi
57 of what she had. How many less percent did Tammy have than Abi in the end? Correct the answer to 1 decimal place.
|
Tammy |
Abi |
Comparing Tammy and Abi at first |
5x7 = 35 u |
2x7 = 14 u |
Before |
7x5 = 35 u |
|
Change |
- 5x5 = - 25 u |
+ 5x5 = + 25 u |
After |
2x5 = 10 u |
39 u |
40% =
40100 =
25The number of coins that Tammy had at first is repeated. Make the number of coins that Tammy had at first the same. LCM of 5 and 7 is 35.
Number of coins that Abi had in the end
= 14 u + 25 u
= 39 u
Number of less coins that Tammy had than Abi in the end
= 39 u - 10 u
= 29 u
Number of less coins that Tammy had than Abi in the end in percent
=
2939 x 100%
≈ 74.4%
Answer(s): 74.4%