Sabrina and Betty shared some erasers. Sabrina had 75% of what Betty had at first. Sabrina then gave Betty
37 of what she had. How many less percent did Sabrina have than Betty in the end? Correct the answer to 1 decimal place.
|
Sabrina |
Betty |
Comparing Sabrina and Betty at first |
4x7 = 28 u |
3x7 = 21 u |
Before |
7x4 = 28 u |
|
Change |
- 3x4 = - 12 u |
+ 3x4 = + 12 u |
After |
4x4 = 16 u |
33 u |
75% =
75100 =
34The number of erasers that Sabrina had at first is repeated. Make the number of erasers that Sabrina had at first the same. LCM of 4 and 7 is 28.
Number of erasers that Betty had in the end
= 21 u + 12 u
= 33 u
Number of less erasers that Sabrina had than Betty in the end
= 33 u - 16 u
= 17 u
Number of less erasers that Sabrina had than Betty in the end in percent
=
1733 x 100%
≈ 51.5%
Answer(s): 51.5%