Xuan and Nora shared some pens. Xuan had 30% of what Nora had at first. Xuan then gave Nora
47 of what she had. How many less percent did Xuan have than Nora in the end? Correct the answer to 1 decimal place.
| |
Xuan |
Nora |
Comparing Xuan
and Nora at first |
10x7 =
70 u |
3x7 =
21 u |
| Before |
7x10 =
70 u |
|
| Change |
- 4x10 =
- 40 u |
+ 4x10 =
+ 40 u |
| After |
3x10 =
30 u |
61 u |
30% =
30100 =
310The number of pens that Xuan had at first is repeated. Make the number of pens that Xuan had at first the same. LCM of 10 and 7 is 70.
Number of pens that Nora had in the end
= 21 u + 40 u
= 61 u
Number of less pens that Xuan had than Nora in the end
= 61 u - 30 u
= 31 u
Number of less pens that Xuan had than Nora in the end in percent
=
3161 x 100%
≈ 50.8%
Answer(s): 50.8%
