Wendy and Jaslyn shared some beads. Wendy had 20% of what Jaslyn had at first. Wendy then gave Jaslyn
58 of what she had. How many less percent did Wendy have than Jaslyn in the end? Correct the answer to 1 decimal place.
|
Wendy |
Jaslyn |
Comparing Wendy and Jaslyn at first |
5x8 = 40 u |
1x8 = 8 u |
Before |
8x5 = 40 u |
|
Change |
- 5x5 = - 25 u |
+ 5x5 = + 25 u |
After |
3x5 = 15 u |
33 u |
20% =
20100 =
15The number of beads that Wendy had at first is repeated. Make the number of beads that Wendy had at first the same. LCM of 5 and 8 is 40.
Number of beads that Jaslyn had in the end
= 8 u + 25 u
= 33 u
Number of less beads that Wendy had than Jaslyn in the end
= 33 u - 15 u
= 18 u
Number of less beads that Wendy had than Jaslyn in the end in percent
=
1833 x 100%
≈ 54.5%
Answer(s): 54.5%