Zoe and Irene shared some stickers. Zoe had 50% of what Irene had at first. Zoe then gave Irene
57 of what she had. How many less percent did Zoe have than Irene in the end? Correct the answer to 1 decimal place.
| |
Zoe |
Irene |
Comparing Zoe
and Irene at first |
2x7 =
14 u |
1x7 =
7 u |
| Before |
7x2 =
14 u |
|
| Change |
- 5x2 =
- 10 u |
+ 5x2 =
+ 10 u |
| After |
2x2 =
4 u |
17 u |
50% =
50100 =
12The number of stickers that Zoe had at first is repeated. Make the number of stickers that Zoe had at first the same. LCM of 2 and 7 is 14.
Number of stickers that Irene had in the end
= 7 u + 10 u
= 17 u
Number of less stickers that Zoe had than Irene in the end
= 17 u - 4 u
= 13 u
Number of less stickers that Zoe had than Irene in the end in percent
=
1317 x 100%
≈ 76.5%
Answer(s): 76.5%
