Diana and Natalie shared some cards. Diana had 10% of what Natalie had at first. Diana then gave Natalie
57 of what she had. How many less percent did Diana have than Natalie in the end? Correct the answer to 1 decimal place.
| |
Diana |
Natalie |
Comparing Diana
and Natalie at first |
10x7 =
70 u |
1x7 =
7 u |
| Before |
7x10 =
70 u |
|
| Change |
- 5x10 =
- 50 u |
+ 5x10 =
+ 50 u |
| After |
2x10 =
20 u |
57 u |
10% =
10100 =
110The number of cards that Diana had at first is repeated. Make the number of cards that Diana had at first the same. LCM of 10 and 7 is 70.
Number of cards that Natalie had in the end
= 7 u + 50 u
= 57 u
Number of less cards that Diana had than Natalie in the end
= 57 u - 20 u
= 37 u
Number of less cards that Diana had than Natalie in the end in percent
=
3757 x 100%
≈ 64.9%
Answer(s): 64.9%
