Jean and Kimberly shared some marbles. Jean had 70% of what Kimberly had at first. Jean then gave Kimberly
47 of what she had. How many more percent did Kimberly have than Jean in the end? Correct the answer to 1 decimal place.
| |
Jean |
Kimberly |
Comparing Jean
and Kimberly at first |
10x7 =
70 u |
7x7 =
49 u |
| Before |
7x10 =
70 u |
|
| Change |
- 4x10 =
- 40 u |
+ 4x10 =
+ 40 u |
| After |
3x10 =
30 u |
89 u |
70% =
70100 =
710The number of marbles that Jean had at first is repeated. Make the number of marbles that Jean had at first the same. LCM of 10 and 7 is 70.
Number of marbles that Kimberly had in the end
= 49 u + 40 u
= 89 u
Number of more marbles that Kimberly had than Jean in the end
= 89 u - 30 u
= 59 u
Number of more marbles that Kimberly had than Jean in the end in percent
=
5930 x 100%
≈ 196.7%
Answer(s): 196.7%
