Sabrina and Elyse shared some beads. Sabrina had 50% of what Elyse had at first. Sabrina then gave Elyse
37 of what she had. How many less percent did Sabrina have than Elyse in the end? Correct the answer to 1 decimal place.
|
Sabrina |
Elyse |
Comparing Sabrina and Elyse at first |
2x7 = 14 u |
1x7 = 7 u |
Before |
7x2 = 14 u |
|
Change |
- 3x2 = - 6 u |
+ 3x2 = + 6 u |
After |
4x2 = 8 u |
13 u |
50% =
50100 =
12The number of beads that Sabrina had at first is repeated. Make the number of beads that Sabrina had at first the same. LCM of 2 and 7 is 14.
Number of beads that Elyse had in the end
= 7 u + 6 u
= 13 u
Number of less beads that Sabrina had than Elyse in the end
= 13 u - 8 u
= 5 u
Number of less beads that Sabrina had than Elyse in the end in percent
=
513 x 100%
≈ 38.5%
Answer(s): 38.5%