Lee, Justin and Henry had a total of 141 stamps. The ratio of the number of stamps that Justin had to the number of stamps that Henry had was 4 : 9. After Lee and Justin each gave away half of their stamps, the 3 children had 111 stamps left. How many stamps did Justin and Henry have at first?
| |
Lee |
Justin |
Henry |
Total |
| Before |
2 p |
4 u |
9 u |
141 |
| Change |
- 1 p |
- 2 u |
|
- 30 |
| After |
1 p |
2 u |
9 u |
111 |
Total number of stamps that Lee and Justin gave away
= 141 - 111
= 30
1 p + 2 u = 30 --- (1)
1 p + 2 u + 9 u = 111
1 p + 11 u = 111 --- (2)
(2) - (1)
(1 p + 11 u) - (1 p + 2 u) = 111 - 30
11 u - 2 u = 81
9 u = 81
1 u = 81 ÷ 9 = 9
Total number of stamps that Justin and Henry had at first
= 4 u + 9 u
= 13 u
= 13 x 9
= 117
Answer(s): 117
