Jeremy, Ahmad and Vincent had a total of 52 beads. The ratio of the number of beads that Ahmad had to the number of beads that Vincent had was 2 : 5. After Jeremy and Ahmad each gave away half of their beads, the 3 children had 41 beads left. How many beads did Ahmad and Vincent have in the end?
| |
Jeremy |
Ahmad |
Vincent |
Total |
| Before |
2 p |
2 u |
5 u |
52 |
| Change |
- 1 p |
- 1 u |
|
- 11 |
| After |
1 p |
1 u |
5 u |
41 |
Total number of beads that Jeremy and Ahmad gave away
= 52 - 41
= 11
1 p + 1 u = 11 --- (1)
1 p + 1 u + 5 u = 41
1 p + 6 u = 41 --- (2)
(2) - (1)
(1 p + 6 u) - (1 p + 1 u) = 41 - 11
6 u - 1 u = 30
5 u = 30
1 u = 30 ÷ 5 = 6
Total number of beads that Ahmad and Vincent had in the end
= 1 u + 5 u
= 6 u
= 6 x 6
= 36
Answer(s): 36
