Luke, Charlie and Tommy had a total of 79 stickers. The ratio of the number of stickers that Charlie had to the number of stickers that Tommy had was 4 : 7. After Luke and Charlie each gave away half of their stickers, the 3 children had 57 stickers left. How many stickers did Charlie and Tommy have in the end?
| |
Luke |
Charlie |
Tommy |
Total |
| Before |
2 p |
4 u |
7 u |
79 |
| Change |
- 1 p |
- 2 u |
|
- 22 |
| After |
1 p |
2 u |
7 u |
57 |
Total number of stickers that Luke and Charlie gave away
= 79 - 57
= 22
1 p + 2 u = 22 --- (1)
1 p + 2 u + 7 u = 57
1 p + 9 u = 57 --- (2)
(2) - (1)
(1 p + 9 u) - (1 p + 2 u) = 57 - 22
9 u - 2 u = 35
7 u = 35
1 u = 35 ÷ 7 = 5
Total number of stickers that Charlie and Tommy had in the end
= 2 u + 7 u
= 9 u
= 9 x 5
= 45
Answer(s): 45
