Fred, Ian and Nick had a total of 148 stickers. The ratio of the number of stickers that Ian had to the number of stickers that Nick had was 6 : 5. After Fred and Ian each gave away half of their stickers, the 3 children had 104 stickers left. How many stickers did Ian and Nick have in the end?
| |
Fred |
Ian |
Nick |
Total |
| Before |
2 p |
6 u |
5 u |
148 |
| Change |
- 1 p |
- 3 u |
|
- 44 |
| After |
1 p |
3 u |
5 u |
104 |
Total number of stickers that Fred and Ian gave away
= 148 - 104
= 44
1 p + 3 u = 44 --- (1)
1 p + 3 u + 5 u = 104
1 p + 8 u = 104 --- (2)
(2) - (1)
(1 p + 8 u) - (1 p + 3 u) = 104 - 44
8 u - 3 u = 60
5 u = 60
1 u = 60 ÷ 5 = 12
Total number of stickers that Ian and Nick had in the end
= 3 u + 5 u
= 8 u
= 8 x 12
= 96
Answer(s): 96
