Nick, Bryan and Julian had a total of 192 coins. The ratio of the number of coins that Bryan had to the number of coins that Julian had was 8 : 7. After Nick and Bryan each gave away half of their coins, the 3 children had 138 coins left. How many coins did Bryan and Julian have in the end?
| |
Nick |
Bryan |
Julian |
Total |
| Before |
2 p |
8 u |
7 u |
192 |
| Change |
- 1 p |
- 4 u |
|
- 54 |
| After |
1 p |
4 u |
7 u |
138 |
Total number of coins that Nick and Bryan gave away
= 192 - 138
= 54
1 p + 4 u = 54 --- (1)
1 p + 4 u + 7 u = 138
1 p + 11 u = 138 --- (2)
(2) - (1)
(1 p + 11 u) - (1 p + 4 u) = 138 - 54
11 u - 4 u = 84
7 u = 84
1 u = 84 ÷ 7 = 12
Total number of coins that Bryan and Julian had in the end
= 4 u + 7 u
= 11 u
= 11 x 12
= 132
Answer(s): 132
