Caden, Jeremy and Ahmad had a total of 94 cards. The ratio of the number of cards that Jeremy had to the number of cards that Ahmad had was 4 : 3. After Caden and Jeremy each gave away half of their cards, the 3 children had 62 cards left. How many cards did Jeremy and Ahmad have at first?
| |
Caden |
Jeremy |
Ahmad |
Total |
| Before |
2 p |
4 u |
3 u |
94 |
| Change |
- 1 p |
- 2 u |
|
- 32 |
| After |
1 p |
2 u |
3 u |
62 |
Total number of cards that Caden and Jeremy gave away
= 94 - 62
= 32
1 p + 2 u = 32 --- (1)
1 p + 2 u + 3 u = 62
1 p + 5 u = 62 --- (2)
(2) - (1)
(1 p + 5 u) - (1 p + 2 u) = 62 - 32
5 u - 2 u = 30
3 u = 30
1 u = 30 ÷ 3 = 10
Total number of cards that Jeremy and Ahmad had at first
= 4 u + 3 u
= 7 u
= 7 x 10
= 70
Answer(s): 70
