Carl, Paul and Daniel had a total of 74 coins. The ratio of the number of coins that Paul had to the number of coins that Daniel had was 4 : 3. After Carl and Paul each gave away half of their coins, the 3 children had 49 coins left. How many coins did Paul and Daniel have in the end?
| |
Carl |
Paul |
Daniel |
Total |
| Before |
2 p |
4 u |
3 u |
74 |
| Change |
- 1 p |
- 2 u |
|
- 25 |
| After |
1 p |
2 u |
3 u |
49 |
Total number of coins that Carl and Paul gave away
= 74 - 49
= 25
1 p + 2 u = 25 --- (1)
1 p + 2 u + 3 u = 49
1 p + 5 u = 49 --- (2)
(2) - (1)
(1 p + 5 u) - (1 p + 2 u) = 49 - 25
5 u - 2 u = 24
3 u = 24
1 u = 24 ÷ 3 = 8
Total number of coins that Paul and Daniel had in the end
= 2 u + 3 u
= 5 u
= 5 x 8
= 40
Answer(s): 40
