Vincent, Michael and Seth had a total of 87 stamps. The ratio of the number of stamps that Michael had to the number of stamps that Seth had was 6 : 7. After Vincent and Michael each gave away half of their stamps, the 3 children had 61 stamps left. How many stamps did Michael and Seth have at first?
| |
Vincent |
Michael |
Seth |
Total |
| Before |
2 p |
6 u |
7 u |
87 |
| Change |
- 1 p |
- 3 u |
|
- 26 |
| After |
1 p |
3 u |
7 u |
61 |
Total number of stamps that Vincent and Michael gave away
= 87 - 61
= 26
1 p + 3 u = 26 --- (1)
1 p + 3 u + 7 u = 61
1 p + 10 u = 61 --- (2)
(2) - (1)
(1 p + 10 u) - (1 p + 3 u) = 61 - 26
10 u - 3 u = 35
7 u = 35
1 u = 35 ÷ 7 = 5
Total number of stamps that Michael and Seth had at first
= 6 u + 7 u
= 13 u
= 13 x 5
= 65
Answer(s): 65
