Harry, Nick and Luke had a total of 95 coins. The ratio of the number of coins that Nick had to the number of coins that Luke had was 6 : 5. After Harry and Nick each gave away half of their coins, the 3 children had 65 coins left. How many coins did Nick and Luke have in the end?
| |
Harry |
Nick |
Luke |
Total |
| Before |
2 p |
6 u |
5 u |
95 |
| Change |
- 1 p |
- 3 u |
|
- 30 |
| After |
1 p |
3 u |
5 u |
65 |
Total number of coins that Harry and Nick gave away
= 95 - 65
= 30
1 p + 3 u = 30 --- (1)
1 p + 3 u + 5 u = 65
1 p + 8 u = 65 --- (2)
(2) - (1)
(1 p + 8 u) - (1 p + 3 u) = 65 - 30
8 u - 3 u = 35
5 u = 35
1 u = 35 ÷ 5 = 7
Total number of coins that Nick and Luke had in the end
= 3 u + 5 u
= 8 u
= 8 x 7
= 56
Answer(s): 56
