Luis, Valen and Ahmad had a total of 58 coins. The ratio of the number of coins that Valen had to the number of coins that Ahmad had was 2 : 3. After Luis and Valen each gave away half of their coins, the 3 children had 44 coins left. How many coins did Valen and Ahmad have in the end?
| |
Luis |
Valen |
Ahmad |
Total |
| Before |
2 p |
2 u |
3 u |
58 |
| Change |
- 1 p |
- 1 u |
|
- 14 |
| After |
1 p |
1 u |
3 u |
44 |
Total number of coins that Luis and Valen gave away
= 58 - 44
= 14
1 p + 1 u = 14 --- (1)
1 p + 1 u + 3 u = 44
1 p + 4 u = 44 --- (2)
(2) - (1)
(1 p + 4 u) - (1 p + 1 u) = 44 - 14
4 u - 1 u = 30
3 u = 30
1 u = 30 ÷ 3 = 10
Total number of coins that Valen and Ahmad had in the end
= 1 u + 3 u
= 4 u
= 4 x 10
= 40
Answer(s): 40
